Maths ncert solutions class 11
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Function as a special type of relation. And the most important part is we can download them in our computer for later use. You just landed on the best place. Therefore, equation 1 becomes This is the Cartesian equation of the required plane. For other questions, please visit to or Solutions.

Visit to main page or of the page. Answer : It is known that the equation of the line through the points, x 1, y 1, z 1 and x 2, y 2, z 2 , is Since the line passes through the points, 3, — 4, — 5 and 2, — 3, 1 , its equation is given by, Therefore, any point on the line is of the form 3 — k, k — 4, 6k — 5. Union and Intersection of sets. Derivative introduced as rate of change both as that of distance function and geometrically. Whenever we compare two quantities, they are more likely to be unequal than equal.

Union and Intersection of sets. The distance d between the points, 2, — 1, 2 and — 1, — 5, — 10 , is Q19 : Find the vector equation of the line passing through 1, 2, 3 and parallel to the planes and. The difficult problems have been simplified and explanations have been given to make learning much easier. If Q is the angle between the given pair of lines, then Q12 : Find the values of p so the line and are at right angles. The Greeks expressed much of what we believe of as geometry around 2000 years ago. Q18 : Find the distance of the point — 1, — 5, — 10 from the point of intersection of the line and the plane. So this page contains notes of most of the class 11 chapters and we also have assignments of most of the chapters that you can practice.

Therefore, the direction cosines are 0, 0, and 1 and the distance of the plane from the origin is 2 units. These are the required tangents from P and Q to circle 0, 3. Q4 : In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin. Therefore, the coordinates of the foot of the perpendicular are d Let the coordinates of the foot of perpendicular P from the origin t Q5 : Find the vector and Cartesian equation of the planes a that passes through the point 1, 0, — 2 and the normal to the plane is. Real valued functions, domain and range of these functions, constant, identity, polynomial, rational, modulus, signum, exponential, logarithmic and greatest integer functions, with their graphs.

Equation of family of lines passing through the point of intersection of two lines. Thus, the equation of the required plane is Q17 : Find the equation of the plane which contains the line of intersection of the planes , and which is perpendicular to the plane. Q2 : If l 1, m 1, n 1 and l 2, m 2, n 2 are the direction cosines of two mutually perpendicular lines, show that the direction cosines of the line perpendicular to both of these are m 1n 2 — m 2n 1, n 1l 2 — n 2l 1, l 1m 2 - l 2m 1. If you are having any suggestion for the improvement, your are welcome. In addition, find the measure of two parts. .

Here, the direction ratios of normal are 1, 2, and — 3 and the point P is 1, 2, — 3. Substituting in equation 1 , we obtain This is the required equation of the plane. Q2 : Show that the line through the points 1, -1, 2 3, 4, -2 is perpendicular to the line through the points 0, 3, 2 and 3, 5, 6. You will find plenty of them here or on the respective chapter page. Let it intersect 0, 3 at two points A and B. Concept Wise is the Teachoo टीचू way of doing the chapter.

Function as a special type of relation. The position vector of this point is Also, the direction ratios of the given line are 3, 7, and 2. General equation of a line. Just use the comment box below to leave any message. One is inductive reasoning which is studied in chapter 4 — mathematical induction and the other is deductive reasoning which we intend to study in this chapter. It can be seen that, Therefore, the given planes are not parallel. Events; occurrence of events, 'not', 'and' and 'or' events, exhaustive events, mutually exclusive events, Axiomatic set theoretic probability, connections with other theories studied in earlier classes.

Sections of a cone: circle, ellipse, parabola, hyperbola, a point, a straight line and a pair of intersecting lines as a degenerated case of a conic section. The plane in equation 1 is perpendicular to Its direction ratios, a2, b2, c2, are 1, — 1, and 1. Q7 : Find the intercepts cut off by the plane Answer : Dividing both sides of equation 1 by 5, we obtain It is known that the equation of a plane in intercept form is , where a, b, c are the intercepts cut off by the plane at x, y, and z axes respectively. We suggest you do all the chapters from Concept Wise, so that your concepts are cleared. We have experienced faculty members who leave no stone unturned in helping the students to score the best. The locus of a point that moves in an identical distance from 2 points, is normal to the line joining both the points. Q15 : Find the shortest distance between the lines and Answer : The given lines are and It is known that the shortest distance between the two lines, , is given by, Comparing the given equations, we obtain Substituting all the values in equation 1 , we obtain Since distance is always non-negative, the distance between the given lines is units.

The coordinates of the foot of the perpendicular are given by ld, md, nd. Most of the chapters we will study in Class 11 forms a base of what we will study in Class 12. Definition of derivative relate it to scope of tangent of the curve, Derivative of sum, difference, product and quotient of functions. This means that the line is in the direction of vector , It is known that the line through position vector and in the direction of the vector is given by the equation, This is the required equation of the given line in vector form. It has 2 legs, 1 with a point and the other with a lead or a pencil.